Home
Class 12
PHYSICS
Two parallel plate capacitors of capacit...

Two parallel plate capacitors of capacitance C each are connected in series with a battery of emf `epsilon`. Then, one of the capacitors is filled with a dielectric of dielectric constane K.
i. Find the change in electric field in the two capacitors, if any
ii. What amount of charge flows through the battery?
iii Find the change in the energy stored in the circuit, if any.

Text Solution

AI Generated Solution

To solve the given problem step by step, we will break it down into three parts as per the question requirements. ### Given: - Two parallel plate capacitors, each with capacitance \( C \). - They are connected in series with a battery of emf \( \epsilon \). - One capacitor is filled with a dielectric of dielectric constant \( K \). ### Part (i): Change in Electric Field in the Two Capacitors ...
Promotional Banner

Topper's Solved these Questions

  • CAPACITOR AND CAPACITANCE

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 4.1|13 Videos

  • CAPACITOR AND CAPACITANCE

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 4.2|32 Videos

  • CAPACITOR AND CAPACITANCE

    CENGAGE PHYSICS ENGLISH|Exercise Integer|5 Videos

  • ATOMIC PHYSICS

    CENGAGE PHYSICS ENGLISH|Exercise ddp.4.3|15 Videos

  • CENGAGE PHYSICS DPP

    CENGAGE PHYSICS ENGLISH|Exercise subjective type|51 Videos

Similar Questions

Explore conceptually related problems

Two parallel plate capacitors, each of capacitance 40 muF, are connected is series. The space between the plates of one capacitor is filled with a dielectric material of dielectric constant K =4. Find the equivalent capacitacne of the system.

Two identical parallel plate air capacitors are connected in series to a battery of emf V. If one of the capacitor is completely filled with dielectric material of constant K, then potential difference of the other capacitor will become

Two capacitor of capacitance 4.0muF and 6.0muF' are connected in series with a battery of 20 V . Find the energy supplied by the battery .

A parallel plate capacitor of capacitance 10 muF is connected across a battery of emf 5 mV. Now, the space between the plates of the capacitors is filled with a deielectric material of dielectric constant K=5. Then, the charge that will flow through the battery till equilibrium is reached is

A parallel capacitor of capacitance C is charged and disconnected from the battery. The energy stored in it is E . If a dielectric slab of dielectric constant 6 is inserted between the plates of the capacitor then energy and capacitance will become.

Two capacitors of capacitance C are connected in series. If one of them is filled with dielectric substance K, what is the effective capacitance?

A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20 V. If a dielectric material of dielectric constant K= (5)/(3) is inserted between the plates, the magnitude of the induced charge will be :

A capacitor of capacitance C, which is initially uncharged , is connected with a battery of emf epsilon . Find the heat dissipated in the circuit during the process of charging .

The terminals of a battery of emf V are connected to the two plates of a parallel plate capacitor. If the space between the plates of the capacitor is filled with an insulator of dielectric constant K, then :

A parallel plate capacitar, of capacitance, 20 mu F , is connected to a 100 V supply. After some time, the battery is disconnected , and the space, between the plates of the capacitor is filled with a dielectric, of dielectric constant 5. Calculate the energy stored in the capacitar (i) before (ii)after dielectric has been put in between its plates.