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A capacitor of capacitance C is charged ...

A capacitor of capacitance `C` is charged to a potential difference `V` from a cell and then disconncted from it. A charge `+Q` is now given to its positive plate. The potential difference across the capacitor is now

Text Solution

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Positive plate is given a charge `Q`, the charge distribution on different surface are shown in.
.
Hence new charge on capacitor is `(CV+Q/2)` The potential difference between the plates will be.
`V'=(CV+Q/2)/C=V+Q/(2C)`
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