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Shows the variation of voltage V across ...

Shows the variation of voltage `V` across the plates of two capacitors `A and B` versus incease in charge Q stored in them. Which of the capacitors has higher capacitance? Give reason for your answer.
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Text Solution

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From the given graphs, find the voltages `V_(A)` and `V_(B)` on capacitors `A` and `B` corresponding to charge `Q` on each of the capacitors.
Clearly, `V_(A)=Q/C_(A)` and `V_(B)=Q/C_(B)`
or `(V_(B))/(V_(A)) = (Q//C_(B))/(Q//C_(A)) = (C_(A))/(C_(B))`
Since, `V_(B) gt V_(A), C_(A) gt C_(B)`, i`.e., the capacitor `A` has the higher capacitance.
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