A capacitor of capacitance `C` is charged to a potential differece `V_(0)`. The terminals of the charged capacitor are then connected to those of an uncharged capacitor of capacitance `C//2`.
a. Compute the original charge of the system.
b. Find the final potential differce across each capacitor.
c. Find the final energy of the system.
d. Calculate the decrease in energy when the capacitors are connected.
e. Where did the ''lost'' energy go?

Explanation

Let's solve the problem step by step.

### Step 1: Compute the Original Charge of the System
The original charge \( Q \) on the capacitor can be calculated using the formula:
\[ Q = C \cdot V_0 \]
where \( C \) is the capacitance of the charged capacitor and \( V_0 \) is the initial potential difference.
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