If you have several `2.0 muF` capacitrors, each capable of withstanding `200 V` without breakdown, how would you assemble a combination that has an equivalent capacitance of
a. `0.4muF`
b. `1.2 muF` each with standing `1000V`?

Explanation

To solve the problem, we need to find the arrangements of capacitors that will give us the desired equivalent capacitance while also ensuring that the voltage rating is met.

### Part a: Achieving an Equivalent Capacitance of 0.4 µF

1. **Understanding Series Connection**: Since we need an equivalent capacitance that is less than the capacitance of each capacitor (2.0 µF), we will connect the capacitors in series. The formula for the equivalent capacitance \(C_{eq}\) in series is given by:
\[ \frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \ldots + \frac{1}{C_n} \]
...