Three capacitors `C_(1),C_(2)` and `C_(3)` are connected as shown in, The potentials of `P,Q`, and `R` are `V_(1),V_(2),` and `V_(3)`, respectively. Find the potential `V_(0)` at the function`O`.
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Explanation

Let `q_(1), q_(2), q_(3)` be charges on capacitors `C_(1), C_(2), C_(3)`, respectively. Then we bave
`V_(1)-V_(0)=q_(1)/C_(1), V_(0)-V_(2)=q_(2)/C_(2), V_(0)-V_(3)=q_(3)/C_(3)`
By function rule, we have `q_(1)=q_(2)+q_(3)`
`(V_(1)-V_(0))C_(1)=(V_(0)-V_(2))C_(2)+(V_(0)-V_(3))C_(3)`
or `V_(0)=(V_(1)C_(1)+V_(2)C_(2)+V_(3)C_(3))/(C_(1)+C_(2)+C_(3))`.