Find the capacitance between A and B if two dielectric slabs (each of thickness d) of dielectric constants `K_(1)` and `K_(2)` and areas `K_(1)` and `K_(2)` and inserted between the plates of a parallel plate capacitor of plate area `A`.
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Explanation

The combination is equivalent to two capacitors connected in parallel.
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`:. C_("equivalent")=C_(1)+C_(2)`
`C_(1)=(A_(1)K_(1)epsilon_(0))/d, C_(2)=(A_(2)K_(2)epsilon)/d`
`:. C_("equivalent")=(K_(1)epsilon_(0)A_(2))/d=(epsilon_(0))/d(K_(1)A_(1)+K_(2)A_(2))`.