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In the circuit shown, C(1)=C(2)=2 muF. C...

In the circuit shown, `C_(1)=C_(2)=2 muF`. Capacitor `C_(1)` is charged to `50 V` and `C_(1)` is charge to `20 V`. After charging they are connected as shown. When `S_(1), S_(2)`, and `S_(3)`, are clsosed,
.

A

`70 muC` of charge will pass through `S_(1)`

B

`100 muC` of chaarge will pass throuth `S_(1)`

C

`70 muC` of charge will pass throuth `S_(3)`

D

`40 muC` of chaarge will pass throuth `S_(3)`.

Text Solution

Verified by Experts

The correct Answer is:
A, C
When switches are open, charges on the capacitor are capacitor are shown. When switches are closed, capacitors become parallel, charges are shown on two capacitors. Comparing two diagrams, it is clear that `70 muC` of charge will pass through switches `S_(1)` and `S_(3)`. Hence choices a and c are correct and choices b and d are wrong.
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