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Capacitance of a parallel plate capacito...

Capacitance of a parallel plate capacitor becomes 4/3 times its original value, if a dielectric slab of thickness `t = d//2` is inserted between the plates (d is the separation between the plates). The dielectric constant of the slab is

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The correct Answer is:
2
(6) `(epsilon_(0)A)/(d-d/2+d/(2k))=4/3(epsilon_(0)A)/d)`. Solve to get `k=2`.
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