The current in a simple series cirucit is 5A. When an additional resistance of `2Omega` is introduced, the current is reduced to 4A. Calculate the resistance of the original circuit. Assume that the applied potential difference is the same in both the cases.

Explanation

To solve the problem, we will use Ohm's Law, which states that \( V = I \times R \), where \( V \) is the voltage, \( I \) is the current, and \( R \) is the resistance.

### Step-by-Step Solution:

1. **Identify the Initial Conditions**:
- The initial current \( I_1 = 5 \, \text{A} \).
- Let the original resistance be \( R \).
- The voltage across the circuit can be expressed as:
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