Calculate the resistance between the terminals A and B of the network shown in fig

Explanation

An equivalent of the given netwrok is shwon in fig is clear from the network of the figure that the resistance of
`2Omega, 4Omega, 4Omega and 2Omega` are connected in parallel with each other.
if `R_p` is the total resistance, then `(1)/(R_p) = (1)/(2) +(1)/(4) +(1)/(4)+(1)/(2) =(2+1+1+2)/(4) = (3)/(2)`
or `R_p = (2)/(3) Omega`