A battery of emf 2.0 volts and internal ...

A battery of emf 2.0 volts and internal resistance `0.10(Omega)`is being charged with a current of 5.0A. What is the potential difference between the terminals of the battery?

Text Solution

Verified by Experts

The current will flow from the positive terminal to the negative
terminal in the battery. During charging, the potential difference
is `V +ir = 2+5xx0.1 = 2.5V.

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