Consider the cicutir shown in fig. the current `i_3` is equal to

Explanation

Suppose current through different paths of the circuit is as
follows.
After applying KVL for loop (1) and loop(2), we get
`28if_1 = -6 -8`
or `i_1 = -(1)/(2)`
And `54i_2 = -6 -12 or i_2 = - (1)/(3)A`
Hence `i_3 = i_1+i_2 = -(5)/(6)A`