In the circuit shown in fig the voltage ...

In the circuit shown in fig the voltage across the `6Omega` resistor is 12V. What is the emf of the battery and the current thorugh the `6Oemga` resistor?

Text Solution

Verified by Experts

Current through `2 Omega` resistor is 6A. Current through `1Omega` resistor
also is 6A.
`xi = V =IR = (6A)(3Omega) = 18V`
Current through `6Omega` resistor is `I = 18//6 = 3A.`

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