Consider the circuit shown in fig. If the switch is closed at t =0, then calculate the values of `I, I_(1)` and `I_(2)` at a. t =0 , b. `= oo`

Explanation

At t = 0, C wil behave as a short circuit, so no current
passes through `R_(2)` and `I = I_(2) = epsilon //R_(1).`
b. `At t = oo, C` will block thr current. So `I_(2) = 0.` and
`I = I_(1) = (epsilon)/(R_(1) + R_(2))`