Determine the current through the battery in the circuit shown in figure.

(a) immediately after the switch S is closed
(b) after a long time.

Explanation

a. Immediately after the swithc is closed,`C_(1)` wil act as a simle
wire due to which `R_(2)` and `R_(3)` will be short - circuited. So,
`I = E//R_(1)`
b. After a long time, `C_(1)` and `C_(2)` will block the current. Current
will pass through onlu `R_(1)` and `R_(2) I =(E )/(R_(1) + R_(3))`