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In the circuit shown in fig. R(1) = 10 O...

In the circuit shown in fig. `R_(1) = 10 Omega, R_(2) = 5 Omega, C_(1) = 1 muF, C_(2) = 2muF,` and E =6V. Calculate the charge on each capactor in the stedy state.

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`I = (E )/(R_1 + R_2) = (6)/(10+20) = (1)/(5)A`

`q_1= C_1V_1 = C_1I R_1 = 1 xx(1)/(5)xx10 = 2muC`
`q_2 = C_2V_2 = 2xx6 = 12muC`
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CENGAGE PHYSICS ENGLISH-ELECTRIC CURRENT AND CIRCUIT-Exercise 5.2
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