At room temperature `(27.0 .^(@)C)` the resistance of a heating element is `100 Omega`. What is the temperature of the element if the resistance is found to be `117 Omega`, given that the temperature coefficient of the material of the resistor is `1.70 xx 10^(-4) .^(@)C^(-1)`.

Explanation

Temperature coefficients of the meterial is given by
`alpha = (R_(2) - R_(1))/(R_(1)(t_(2) - t_(1))) or 1.790xx10^(-4) = (117 - 100)/(100(t_(2) - 27))`
or `t_(2) = 1000 +27 =1027^(@)C`