In the circuit diagram shown in find the current through the `1Omega` resistor.

Explanation

`((v -10)-10)/(2)+(v-0)/(2)+(v-5)/(1)=0 or v=(30)/(4)=(15)/(2)V`

Current throgh `1Omega` resistor is `I = (v-5)/(1) = (15)/(2) - 10 = (5)/(2)A`