In the above question, what would have been the change in current in A if battery were some internal resistance.

Options

A. no change
B. decreases
C. increases
D. cannot say

Explanation

To find the change in current in circuit A when a battery with internal resistance is introduced, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Circuit**: Initially, we have a circuit powered by a battery with an electromotive force (EMF) \( E \) and no internal resistance. The current flowing through the circuit is given by Ohm's Law.

2. **Introduce Internal Resistance**: When we introduce an internal resistance \( R_1 \) in the battery, the effective voltage across the external circuit will change. The terminal voltage \( V \) of the battery can be expressed as:
\[ V = E - I R_1 \]
where \( I \) is the current flowing through the circuit.

3. **Determine the Total Resistance**: If there are additional resistors in the circuit, we need to consider the total resistance \( R \) of the external circuit. If the resistors are in series, the total resistance remains \( R \). If they are in parallel, we need to calculate the equivalent resistance.

4. **Calculate the New Current**: The new current \( I' \) flowing through the circuit with the internal resistance can be calculated using Ohm's Law:
\[ I' = \frac{V}{R} = \frac{E - I R_1}{R} \]
Here, \( I \) represents the current before the internal resistance was introduced.

5. **Compare the Currents**: In the original case without internal resistance, the current was:
\[ I = \frac{E}{R} \]
Now, with the internal resistance, we have:
\[ I' = \frac{E - I R_1}{R} \]
Since \( E - I R_1 < E \), it is evident that \( I' < I \).

6. **Conclusion**: The introduction of internal resistance in the battery leads to a decrease in the current flowing through the circuit.

### Final Answer:
The current in circuit A decreases when the battery has some internal resistance.

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