In the circuit shown in fig. find the maximum energy stored on the capacitor. Initially, the capacitor was uncharged.

Options

A. `150muC`
B. `100muC`
C. `50muC`
D. zero

Answer

D

Explanation

The current in the circuit is `I = (12//12) = 1A.`
Potential across d and C is `12 V -3 xx1V = 9V`
Capacitance across d and e is `C = (1xx2)/(1+2) = (2)/(3)muF`
Therefore, charge on either capacitor is `(2)/(3)xx9 = 6muC.`