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In the circuit shown switch S is closed ...

In the circuit shown switch `S` is closed at `t=0`. Let `i_1` and `i_2` be the current at any finite time t then the ratio `i_1/i_2`

A

is constant

B

increases with time

C

decreases with time

D

first increases, then decreases

Text Solution

Verified by Experts

The correct Answer is:
B

From the given situation, we have
`i_(1) = (V)/(R ) (e^(-t//RC))` and `i_(2) = (V)/(R )(e^(-t//3RC))`
`(i_(1))/(I_(2))=(e )^((2t)/(3RC))` which increases with time
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