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A battery of emf E and internal resistan...

A battery of emf E and internal resistance r is connected across a resistance R. Resistance R can be adjusted to any value greater then or equla to zero. A graph is plotted between the current passing through the resistance (I) and potential (V) across it. Select the correct alternatives.

A

Internal resistance of the battery is `5 Omega`

B

Emf of the battery is 10V

C

Maximum current that can be taken from the battery is 2A.

D

V - I graph can never be a straight lines as shown in fig.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
Potential difference acoss resistance is equal to the potential
difference across the terminals of the battery. So V = E - lr.
This is an equation of a straight line. Comparing this with the given graph, we can see that E = 10V and 1`r = 5 Omega.` Also
`I_(max) = (E )/(r ) = (10)/(5) =2A`
When external resistance R =0.
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