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What shunt resistance is required to mak...

What shunt resistance is required to make the 1 mA, `20Omega` galvanometer into an ammeter with a range of O to 50 mA?

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We have `I_(2) = 1.00mA=1.00xx 10^(-3) A` and `R_(2) = 2.0.0 Omega`, and the ammetre should be able to handle maximum current ,
`I = 50.0 xx 10^(-3) A`.
Solving equation `I_(g) r_(g) = (I - I_(g)) R_(S)` for `R_(S)`, we get
`R_(S) = (I_(g)R_(g))/(I - I_(g)) = ((1.00 xx 10^(-3) A)(20.0 Omega))/(50.0 xx 10^(-3) A- 1.00 xx 10^(-3) A) = 0.408 Omega`
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