Home
Class 12
PHYSICS
In the experiment of calibration of volt...

In the experiment of calibration of voltmeter, a standard
cell of emf `1.1 V` is balanced against `440 cm` of
potentiometer wire. The potentail difference across the
ends of a resistance is found to balance aginst `220 cm` of the wire. The corresponding reading of the voltmeter is `0.5 V`. Find theerror in the reading of voltmeter.

Text Solution

AI Generated Solution

To solve the problem of finding the error in the reading of the voltmeter, we can follow these steps: ### Step 1: Calculate the Potential Gradient (K) The potential gradient (K) can be calculated using the formula: \[ K = \frac{V}{L} \] where \( V \) is the EMF of the standard cell and \( L \) is the length of the potentiometer wire. Given: ...
Promotional Banner

Topper's Solved these Questions

  • ELECTRICAL MEASURING INSTRUMENTS

    CENGAGE PHYSICS ENGLISH|Exercise Subjective|18 Videos
  • ELECTRICAL MEASURING INSTRUMENTS

    CENGAGE PHYSICS ENGLISH|Exercise Single Correct|94 Videos
  • ELECTRICAL MEASURING INSTRUMENTS

    CENGAGE PHYSICS ENGLISH|Exercise Solved Examples|4 Videos
  • ELECTRIC POTENTIAL

    CENGAGE PHYSICS ENGLISH|Exercise DPP 3.5|15 Videos
  • ELECTROMAGNETIC INDUCTION

    CENGAGE PHYSICS ENGLISH|Exercise compression type|7 Videos

Similar Questions

Explore conceptually related problems

In an experiment for calibration of voltmeter, a standard cell of emf 1.5V is balanced at 300cm length of potentiometer wire. The P.D across a resistance in the circuit is balancedat 1.25m. If a voltmeter is connected across the same resistance. It reads 0.65V. The errorin the volt meter is

In the experiment of calibration of a voltmeter, a 1.1 V standard cell gets balanced at 440 cm length of wire. The balancing length corresponding to a potential difference between the ends of a resistance comes out to be 190 cm. A voltmeter shows 0.5 V for this potential difference. The error in the reading of voltmeter will be

For a cell of e.m.f. 2 V , a balance is obtained for 50 cm of the potentiometer wire. If the cell is shunted by a 2Omega resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is

If potential gradient on wire PQ is 0.01 V//m then the reading of voltmeter is :

A 10 m long potentiometer wire carries a steady current. A standard cell of emf 1.018 V is balanced against a length of 254.5 cm of the wire. What is the potential gradient across the potentiometer wire ?

In a potentiometer experiment, the galvanometer shows no deflection when a cell is connected across 60 cm of the potentiometer wire. If the cell is shunted by a resistance of 6 Omega , the balance is obtained across 50 cm of the wire. The internal resistance of the cell is

A voltmeter of resistance 994Omega is connected across a cell of emf 1 V and internal resistance 6Omega . Find the potential difference across the voltmeter, that across the terminals of the cell and percantage error in the reading of the voltmeter.

A voltmeter reads the potential difference across the terminals of an old battery as 1.40 V , while a potentiometer reads its voltage to be 1.55 V . The voltmeter resistance is 280 Omega .

In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35.0 cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63.0 cm, what is the emf of the second cell ?

In a potentiometer circuit, the emf of driver cell is 2V and internal resistance is 0.5 Omega . The potentiometer wire is 1m long . It is found that a cell of emf 1V and internal resistance 0.5 Omega is balanced against 60 cm length of the wire. Calculate the resistance of potentiometer wire.