A milliammeter of range `10 mA` and resistance `9 Omega` is joned in a circuit as shown. The meter gives full scale deflection for current `I `when A and B are used as its terminals,i.e.,current enters at A and leaves at B (C is left isolated). The value of I is

Options

A. `100 mA`
B. `900 mA`
C. `1 A`
D. `1.1 A`

Answer

C

Explanation

`i_(g) = 10 mA = 0.01 A`
`V_(A) - V_(B) = (I - i_(g)) 0.1 = i_(g) (9 + 0.9)`
or `I = (10 xx 0.01)/(0.1) = 1A`