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A galvanometer has a resistance of 3663O...

A galvanometer has a resistance of `3663Omega`. A shunt `S` is connected across it such that (`1//34`) of the total current passes through the galvanometer. Then the value of the shunt is

A

`3663 Omega`

B

`111 Omega`

C

`107.7 Omega`

D

`3555.3 Omega`

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The correct Answer is:
To find the value of the shunt resistance \( S \) connected across the galvanometer, we can follow these steps: ### Step 1: Define the total current and current through the galvanometer Let the total current be \( I \). According to the problem, \( \frac{1}{34} \) of the total current passes through the galvanometer. Therefore, the current through the galvanometer \( I_g \) can be expressed as: \[ I_g = \frac{I}{34} \] ### Step 2: Calculate the current through the shunt The current through the shunt \( I_s \) can be calculated by subtracting the current through the galvanometer from the total current: \[ I_s = I - I_g = I - \frac{I}{34} = I \left(1 - \frac{1}{34}\right) = I \left(\frac{34 - 1}{34}\right) = I \left(\frac{33}{34}\right) \] ### Step 3: Write the voltage across the galvanometer The voltage across the galvanometer \( V_{AB} \) can be expressed using Ohm's law: \[ V_{AB} = I_g \cdot R_g = \left(\frac{I}{34}\right) \cdot R_g \] where \( R_g = 3663 \, \Omega \) is the resistance of the galvanometer. ### Step 4: Write the voltage across the shunt The voltage across the shunt \( V_{AB} \) can also be expressed as: \[ V_{AB} = I_s \cdot S = \left(I \cdot \frac{33}{34}\right) \cdot S \] ### Step 5: Set the voltages equal Since the galvanometer and the shunt are connected in parallel, the voltages across both must be equal: \[ \left(\frac{I}{34}\right) \cdot R_g = \left(I \cdot \frac{33}{34}\right) \cdot S \] ### Step 6: Cancel \( I \) from both sides Assuming \( I \neq 0 \), we can cancel \( I \) from both sides: \[ \frac{R_g}{34} = \frac{33}{34} \cdot S \] ### Step 7: Solve for the shunt resistance \( S \) Now, we can solve for \( S \): \[ R_g = 33S \] \[ S = \frac{R_g}{33} \] Substituting the value of \( R_g \): \[ S = \frac{3663}{33} \approx 111.0 \, \Omega \] ### Final Answer Thus, the value of the shunt resistance \( S \) is approximately \( 111.0 \, \Omega \). ---

To find the value of the shunt resistance \( S \) connected across the galvanometer, we can follow these steps: ### Step 1: Define the total current and current through the galvanometer Let the total current be \( I \). According to the problem, \( \frac{1}{34} \) of the total current passes through the galvanometer. Therefore, the current through the galvanometer \( I_g \) can be expressed as: \[ I_g = \frac{I}{34} \] ...
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