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In the connection shown in the figure, i...

In the connection shown in the figure, initially the switch K is open and the capacitor is uncharged. Then the switch is closed, and the capacitor is charged up to the steady state and the switch is opened again. Determine the values indicated by the values indicated by the ammeter.
`[Given V_0 = 30 V, R_1 = 10k Omega, R_2 = 5kOmega`]
.
A long time after the switch was closed.

A

`2 mA`

B

`3 mA`

C

`6 mA`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Just after closing, capacitor behaves as a short circuit and all current flows through it, hence ammeter reads zero.
After a long time, capacitor behaves like an open circuit and no current flows through it. Therefore,
`I = (V_(0))/(R_(1) + R_(2)) = (30)/(10 + 5) = 2 mA`
Just after reopening, potential difference across `R_(2)` remains the same as charge on the capacitor does not change intially, hence current remains the same.
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