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AB is a potentiometer wire of length 100...

`AB` is a potentiometer wire of length `100 cm`. When a cell `E_(2)` is connected across `AC`, where `AC = 75 cm`, no current flows from `E_(2)`. The internal resistance of the cell `E_(1)` is negligible.

Find emf of the cell `E_(2)`.

A

`2 V`

B

`1.5 V`

C

`1 V`

D

`1.75 V`

Text Solution

Verified by Experts

The correct Answer is:
B
`k = (E_(1))/(100) = (2)/(100) 0.02 V cm^(-1)`
`E_(2) = k(75) = 0.02 xx 75 = 1.5 V`
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