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The ammeter shown in figure consists of ...

The ammeter shown in figure consists of a` 480(omega)`coil connected in parallel to a` 20 (omega)` shunt. Find the reading of the ammeter.

Text Solution

Verified by Experts

The correct Answer is:
`(8)`
Equivalent resistance of the ammeter is
`((480)(20 Omega))/(480 Omega + 20 Omega) = 19.2 Omega`
The equivalent resistance of the circuit is `140.8 Omega + 19.2 Omega = 160 Omega`. Therefore, current, `I = 20 V//160 Omega = (1//8) A`
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