A dry cell of emf `1.5 V` and internal resistance `0.10 Omega` is connected across a resistor in series with a very low resistance ammeter. When the circuit is switched on , the ammeter reading settles to a steady value of `2.0 A`.
(i) What is the steady rate of chemical energy consumption of the cell ?
(ii) What is the steady rate of energy dissipation inside the cell ?
(ii) What is the steady rate of energy dissipation inside the resistor ?
(iv) What is the steady power out put of the source?

Explanation

To solve the problem step by step, we will address each part of the question sequentially.

### Given Data:
- EMF of the dry cell, \( E = 1.5 \, \text{V} \)
- Internal resistance of the dry cell, \( r = 0.1 \, \Omega \)
- Steady current, \( I = 2.0 \, \text{A} \)

### (i) Steady Rate of Chemical Energy Consumption of the Cell
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