Two wires made of tinned copper having identical cross section `( = 10^(-6) m^(2))` and lengths `10 and 15 cm` are to be used as fuses. Show that the fuses will melt at the same value of current in each case.

Explanation

To show that the two wires made of tinned copper will melt at the same value of current, we can follow these steps:

### Step 1: Understand the Heat Produced by the Current
The heat produced per second (power) in a wire due to the current can be expressed using the formula:
\[ P = I^2 R \]
where \( P \) is the power (heat produced per second), \( I \) is the current, and \( R \) is the resistance of the wire.

### Step 2: Calculate the Resistance of Each Wire
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