In the circuit shown in fig the heat produced in the 5 ohm resistor due to the current flowing through it is 10 calories per second.

The heat generated in the 4 ohms resistor is

Options

A. `1 Cals^(-1)`
B. `2 Cals^(-1)`
C. `3 Cals^(-1)`
D. `4 Cals^(-1)`

Answer

B

Explanation

Let current is `5 Omega` resistors be `I_(1)` and `in 4 Omega` resistors be `I_(2)`, then `I_(2)//I_(1) = (1//2)`. The heat generated in the ` 5 Omega` resistor is `10 cals^(-1)`
Given `I_(1)^(2) xx 5 = 10 or (( 2 I ^(2))^(2) xx 5 = 10 or I_(2)^(2) = (1)/(2)`. Heat in the `4 Omega` resistor will be `(I_(2)^(2))^(2) xx 4 = 2 cal s^(-1)`.