Two electric bulbs `A and B` are rated `60 and 100 W`, respectively. If they are connected in parallel to the same source , then

Options

A. both the bulbs draw the same current
B. bulb `A` draws more current than bulb `B`
C. bulb `B` draws more current than bulb `A`
D. currents drawn in the bulbs are in the ratio of their resistances

Explanation

To solve the problem, we need to analyze the situation of two electric bulbs rated at different powers when connected in parallel. Here’s a step-by-step solution:

### Step 1: Understand the Ratings of the Bulbs
The bulbs are rated as follows:
- Bulb A: 60 W
- Bulb B: 100 W

### Step 2: Use the Power Formula
The power (P) of an electrical device can be expressed in terms of voltage (V) and resistance (R) using the formula:
\[ P = \frac{V^2}{R} \]
Since both bulbs are connected in parallel, they are subjected to the same voltage (V).

### Step 3: Relate Power to Resistance
From the power formula, we can express the resistance of each bulb:
- For Bulb A:
\[ R_A = \frac{V^2}{P_A} = \frac{V^2}{60} \]
- For Bulb B:
\[ R_B = \frac{V^2}{P_B} = \frac{V^2}{100} \]

### Step 4: Compare the Resistances
Now, we can compare the resistances:
- Since \( P_A < P_B \), it follows that \( R_A > R_B \).
- This means Bulb A has a higher resistance than Bulb B.

### Step 5: Use Ohm’s Law to Find Current
According to Ohm's Law, the current (I) through a resistor is given by:
\[ I = \frac{V}{R} \]
Thus, the currents through the bulbs can be expressed as:
- For Bulb A:
\[ I_A = \frac{V}{R_A} \]
- For Bulb B:
\[ I_B = \frac{V}{R_B} \]

### Step 6: Compare the Currents
Since \( R_A > R_B \), we can conclude:
\[ I_A < I_B \]
This means that Bulb B draws more current than Bulb A.

### Step 7: Conclusion
Based on our analysis:
- **Correct Answer:** Bulb B draws more current than Bulb A.

### Step 8: Check the Options
Now, let's check the options provided in the question:
- Option A: Both bulbs draw the same current. (Incorrect)
- Option B: Bulb A draws more current than Bulb B. (Incorrect)
- Option C: Bulb B draws more current than Bulb A. (Correct)
- Option D: Current drawn in the bulbs is in the ratio of their resistance. (Incorrect)

Thus, the correct option is **C**.

---