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In the circuit shown in Fig. 7.45,...

In the circuit shown in Fig. 7.45,

A

Power supplied by the battery is `200 W`

B

current flowing in the circuit is `5 A`

C

Potential difference across the `4 Omega` resistance is equal to the potential difference across the `6 Omega` resistance

D

current in wire `AB` is zero

Text Solution

Verified by Experts

The correct Answer is:
A, C
Resistors ` 4 Omega and 6 Omega` are short - circuited. Therefore, no current will flow through these resistances. Current passing through the battery is `I = (20//2) = 10 A`. This is also the current passing in wire `AB from B to A`. Power supplied by the battery is `P = EI = (20)(10) = 200 W`. potential difference across the `4 Omega` resistance is equal to the potential difference across the `6 Omega` resistance.
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