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Statement I: Heater wire must have high ...

Statement I: Heater wire must have high resistance than connecting wires and high netallic point.
Statement II : If resistance is high , the electrical conductivity will be less.

A

Statement I is True , Statement II is True , Statement II is a correct explanation for Statement I.

B

Statement I is True, Statement II is True , Statement II is NOT a correct explanation for statement I.

C

Statement I is True , Statement is False.

D

Statement I is False, Statement II is True.

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will break down the reasoning step by step. ### Step 1: Understanding Statement I **Statement I**: "Heater wire must have high resistance than connecting wires and high melting point." - **Analysis**: - The heater wire is designed to convert electrical energy into heat energy. For this to happen efficiently, it must have a higher resistance than the connecting wires. This is because, according to the formula for power (P = I²R or P = V²/R), if the resistance (R) is high, the power (P) dissipated as heat in the heater will also be high, assuming the current (I) remains constant. - Additionally, the heater wire must have a high melting point to prevent it from melting due to the heat generated during operation. If the melting point is low, the wire could fail and stop functioning. **Conclusion for Statement I**: This statement is correct. ### Step 2: Understanding Statement II **Statement II**: "If resistance is high, the electrical conductivity will be less." - **Analysis**: - Electrical resistance (R) and electrical conductivity (σ) are inversely related. The relationship can be expressed as: \[ R = \frac{\rho L}{A} \] where ρ is resistivity, L is the length of the conductor, and A is the cross-sectional area. - Conductivity (σ) is the reciprocal of resistivity: \[ \sigma = \frac{1}{\rho} \] - Therefore, if resistance is high, it implies that resistivity is high, which means conductivity must be low. This confirms that higher resistance corresponds to lower conductivity. **Conclusion for Statement II**: This statement is also correct. ### Step 3: Final Conclusion - Both statements are correct, but they do not provide a direct explanation for each other. Thus, while both are true, Statement II does not serve as a correct explanation for Statement I. ### Final Answer: - **Statement I is true.** - **Statement II is true.** - **Statement II is not the correct explanation for Statement I.** ---

To analyze the statements provided in the question, we will break down the reasoning step by step. ### Step 1: Understanding Statement I **Statement I**: "Heater wire must have high resistance than connecting wires and high melting point." - **Analysis**: - The heater wire is designed to convert electrical energy into heat energy. For this to happen efficiently, it must have a higher resistance than the connecting wires. This is because, according to the formula for power (P = I²R or P = V²/R), if the resistance (R) is high, the power (P) dissipated as heat in the heater will also be high, assuming the current (I) remains constant. - Additionally, the heater wire must have a high melting point to prevent it from melting due to the heat generated during operation. If the melting point is low, the wire could fail and stop functioning. ...
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