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A parallel plate capacitor of capacitanc...

A parallel plate capacitor of capacitance `10 muF` is connected across a battery of emf 5 mV. Now, the space between the plates of the capacitors is filled with a deielectric material of dielectric constant K=5. Then, the charge that will flow through the battery till equilibrium is reached is

A

`250 muC`

B

`250 nC`

C

`200 nC`

D

`200 muC`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the initial charge stored in the capacitor The initial charge \( Q \) stored in a capacitor is given by the formula: \[ Q = C \times V \] where: - \( C \) is the capacitance, - \( V \) is the voltage (emf of the battery). Given: - \( C = 10 \, \mu F = 10 \times 10^{-6} \, F \) - \( V = 5 \, mV = 5 \times 10^{-3} \, V \) Substituting the values: \[ Q = (10 \times 10^{-6}) \times (5 \times 10^{-3}) = 50 \times 10^{-9} \, C = 50 \, nC \] ### Step 2: Calculate the new capacitance after inserting the dielectric When a dielectric material is inserted between the plates of a capacitor, the new capacitance \( C' \) can be calculated using the formula: \[ C' = K \times C \] where \( K \) is the dielectric constant. Given: - \( K = 5 \) Substituting the values: \[ C' = 5 \times (10 \times 10^{-6}) = 50 \times 10^{-6} \, F = 50 \, \mu F \] ### Step 3: Calculate the new charge stored in the capacitor with the dielectric The new charge \( Q' \) stored in the capacitor after the dielectric is inserted is given by: \[ Q' = C' \times V \] Substituting the values: \[ Q' = (50 \times 10^{-6}) \times (5 \times 10^{-3}) = 250 \times 10^{-9} \, C = 250 \, nC \] ### Step 4: Calculate the charge that flows through the battery The charge that flows through the battery until equilibrium is reached is the difference between the new charge and the initial charge: \[ \Delta Q = Q' - Q \] Substituting the values: \[ \Delta Q = 250 \, nC - 50 \, nC = 200 \, nC \] ### Final Answer The charge that will flow through the battery till equilibrium is reached is: \[ \Delta Q = 200 \, nC \] ---

To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the initial charge stored in the capacitor The initial charge \( Q \) stored in a capacitor is given by the formula: \[ Q = C \times V \] where: ...
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