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The equivalent capacitance between point...

The equivalent capacitance between points A and B is

A

`(epsilon_0A)/(d)`

B

`(2epsilon_0A)/d`

C

`(3epsilon_0A)/d`

D

`(epsilon_0A)/d`

Text Solution

Verified by Experts

The correct Answer is:
A

Given paltes can be rearranged as shown
`C_(1)=(epsilon_(0)A)/(d),C_(2)=(epsilon_(0)A)/(2d)`
`C_(3)=(epsilon_(0)A)/(3d),C_(4)=(epsilon_(0)A)/(2d),C_(5)=(epsilon_(0)A)/(d)`
`C_(1)` and `C_(2)` are in series and its effective capacity is
`((epsilon_(0)A)/(d)xx(epsilon_(0)A)/(2d))/((epsilon_(0)A)/(d)+(epsilon_(0)A)/(2d))=(epsilon_(0)A)/(3d)`
effective capacitance of `C_(4)`
and `C_(3)=(epsilon_(0)A)/(3d)`
`C_(AB)=(epsilon_(0)A)/(3d)+(epsilon_(0)A)/(3d)+(epsilon_(0)A)/(3d)=(epsilon_(0)A)/(d)`
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