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In the circuit shown, a capacitance 3muF...

In the circuit shown, a capacitance `3muF` is charged form a battery of emf `6V` with switch connected to terminal P. The switch is now connected to Q. This charges the `6muF` capacitor from the `3muF` one. What is the new potential difference across combination?

A

`1 V`

B

`2 V`

C

`4 V`

D

`6 V`

Text Solution

Verified by Experts

The correct Answer is:
B
b. Initially at switch position `Q`, by conservation of charge, the voltage `V` across the two capacitors is thus given by
`q=q_(1)+q_(2)=C_(1)V+C_(2)V=(C_(1)+C_(2))V`
or `18=(3+6)V`
or `V=(18//9)=2V`
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