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Two capacitors A and B with capacities C...

Two capacitors A and B with capacities `C_1 and C_2` are charged to potential difference of `V_1 and V_2` respectively. The plates of the capacitors are connected as shown in the figure with one wire free from each capacitor. The upper plate of A is positive and that of B is negative. An uncharged capacitor of capacitance `C_3` and lead wires falls on the free ends to complete circuit, then

A

the final charge on each capacitor are same to each other

B

the final sum of charge on plates a and d is `C_1V_1`.

C

the final sum of charge on plates b and g is `C_2V_2 - C_1V_1`

D

both (b) and(c ) are correct.

Text Solution

Verified by Experts

The correct Answer is:
D
d. Charge on positive plate of `A` is `C_(1)V_(1)`.
Charge on negative plate of `B` is `-C_(2)V_(3)`. When `d` plate of capacitor `C` is connected with the plate of ``, then the total charge of `(d,a)` plate system will be `C_(1)V_(1)` (conservation of charge). Similarty on `(c,s)` plates, total charge will be `-C_(2)V_(2)`. The total charge on `(h,g)` plate system will be `+C_(2)V_(2)-C_(1)V_(1)`.
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