Home
Class 12
PHYSICS
The capacitor plates are fixed on an inc...

The capacitor plates are fixed on an inclined plane and connected to a battery of emf E. The capacitor plates have plate area a, length l, and the distance between them is d. A dielectric constant K is inserted into the capacitor and tied to mass M by a massless string as shown in the figure Find the value of M for which the slab will stay in equilibriu. There is no friction between slab and plates.

A

`m/2 + (E^2epsilon_0A(k-1))/(2lgd)`

B

`m/2 - (E^2epsilon_0A(k-1))/(2lgd)`

C

`m/2 + (E^2epsilon_0A(k-1))/(lgd)`

D

`m/s - (E^2epsilon_0A(k-1))/(lgd)`.

Text Solution

Verified by Experts

The correct Answer is:
A

For equilibrium, we have
`T=Mg`
And `T=F+sin30^(@)`
or `Mg=F+(Mg)/(2)`
or `m=(m)/(2)+(F)/(g)=(m)/(2)+(E^(2)epsilonA(K-1))/(2lgd)`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS ENGLISH|Exercise Assertion and Reason Type|8 Videos
  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS ENGLISH|Exercise Comprehension Type|94 Videos
  • MAGNETIC FIELD AND MAGNETIC FORCES

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Correct Answer type|2 Videos
  • MISCELLANEOUS VOLUME 5

    CENGAGE PHYSICS ENGLISH|Exercise Integer|12 Videos

Similar Questions

Explore conceptually related problems

Find the capacitance of a capacitor if the area of its plates is S, the distance between the plates is d_(0) and a dielectric sheet of the thickness dltd_(0) is inserted into the capacitor (Fig. 25.4)

The capacitor shown has square plates of side L and has gap d between the photos. In the dielectric constant of the materiale of the slab is k , the capacitance of the capacitor is

When a dielectric slab is inserted between the plates of one of the two identical capacitors shown in the figure then match the following:

A capacitor and a bulb are connected in series with a source of alternating emf. If a dielectric slab is inserted between the plates of the capacitor, then

A dielectric slab is inserted between the plates of an isolated capacitor. The force between the plates will

A parallel plate capacitor is connected across a battery. Now, keeping the battery connected, a dielectric slab is inserted between the plates. In the process,

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

Find the capacitances of the capacitance of the capacitors shown In figure .The plate area is A and the separation between the plate is d . Different dielectric slabe in a particular part of the figure area of the same thickness and the entire gap between the plate is filled with the dielectric slabs.

The capacitance of a parallel plate capacitor with plate area A and separation d is C . The space between the plates in filled with two wedges of dielectric constants K_(1) and K_(2) respectively. Find the capacitance of resulting capacitor.

A parallel capacitor of capacitance C is charged and disconnected from the battery. The energy stored in it is E . If a dielectric slab of dielectric constant 6 is inserted between the plates of the capacitor then energy and capacitance will become.