Home
Class 12
PHYSICS
The left plate of the capacitor shown in...

The left plate of the capacitor shown in the figure above carries a charge `+Q` while the right plate is uncharged at `t=0`. The total charge on the right plate after closing the switch will be:

A

`Q/2 + Cepsilon`

B

`Q/2-Cepsilon`

C

`-Q/2`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
b. Electric field between the capacitor plates:
`E=(Q+x)/(2Aepsilon_(0))+(x)/(2Aepsilon_(0))=(1)/(2Aepsilon_(0))[Q+2x]`
Potential difference `=Ed=(d)/(2Aepsilon_(0))[Q+2x]=epsilon`
`epsilon=(Q+2x)/(2C)-x=(Q)/(2)-Cepsilon`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS ENGLISH|Exercise Assertion and Reason Type|8 Videos

  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS ENGLISH|Exercise Comprehension Type|94 Videos

  • MAGNETIC FIELD AND MAGNETIC FORCES

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Correct Answer type|2 Videos

  • MISCELLANEOUS VOLUME 5

    CENGAGE PHYSICS ENGLISH|Exercise Integer|12 Videos

Similar Questions

Explore conceptually related problems

Consider the situation shown in the figure. The capacitor A has a charge q on it whereas B is uncharged. The charge appearing on the capacitor B a long 7 time after the switch is closed is : .

Conisder the istuation shown in the figure. The capacitor A has a charge q on it whereas B is unchanged. The charge appearing on the capacitor B a long time after the switch is closed is

In the circuit shown in figure, the capacitor is charged with a cell of 5V .If the switch is closed at t=0 , then at t=12s , charge on the capacitor is

The plates of a capacitor of capacitance C are given the charges Q_1 and Q_2 as shown in figure. Now the switch is closed at t =0. Find the charges on plates after time t.

The metal plate on the left in Fig, carries a charge +q . The metal plate on the right has a charge of -2q . What charge will flow through S when it is closed if the central plate is initially neutral ?

In the figure shown below ,the charge on the left plate of the 10mu F capacitor is -30 mu C. The charge on the right plate of the 6 muF capactior is :

Four metallic plates placed as shown in the figure. Plate 2 is given a chart Q whereas all other plates are uncharged. Plates 1 and 4 are joined together. The area of each plate is same The charge appearing on the right side of plate 3 is

Four metallic plates placed as shown in the figure. Plate 2 is given a chart Q whereas all other plates are uncharged. Plates 1 and 4 are joined together. The area of each plate is same The charge appearing on the right side of plate 4 is

One plate of a capacitor of capacitance 2muF has total charge +10muC and its other plate has total charge +40muC . The potential difference between the plates is (in Volt).

The figure shows an RC circuit with a parallel plate capacitor. Before switching on the circuit, plate A of the capacitor has a charge. -Q_(0) while plate B has no net charge. If at t = 0 , the switch is closed then after how much time (in seconds) will the net charge on plate A becomes zero? [Given : C = 1 mu F, Q_(0) = 1 mC, epsilon = 1000 V and R = (2 xx 10^(6))/(ln 3) Omega]