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An electric dipole is placed in a unifor...

An electric dipole is placed in a uniform electric field `vec(E )` of magnitude `40N//C`. Graph shows the magnitude of the square on the dipole versus the angle `theta` between the field `vec(E )` and the dipole moment `vec(p)`. The magnitude of dipole moment `vec(p)` is equal to:

A

`2.5 xx 10^(-28)Cm`

B

`2.0 xx 10^(-25) Cm`

C

`1.25 xx 10^(-28) Cm`

D

`5.0 xx 10^(-28) Cm`

Text Solution

Verified by Experts

The correct Answer is:
C
`overset(rarr)tau=overset(rarr)pxxoverset(rarr)E`
`vectau=vecpxxvecE`
`tau_("mas")=pE`
or `50xx10^(-28)=p40` or `p=1.25xx10^(-28)C`
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