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A plane sheet has a uniformly distribute...

A plane sheet has a uniformly distributed charge. Origin is selected at the middle of the sheet (in yz plane). A charge `+Q` is moved from point A (10a, 2a,0) to point B (10a,0,2a) along a circle and then to point C(10a, 0, 0). If the initial electrostatic potential energy is `U_0`, what will be final electrostatic potential energy?

A

zero

B

`U_0`

C

`U_0(sqrt2)`

D

`U_0/2`

Text Solution

Verified by Experts

The correct Answer is:
B
b. The electric field will be as shown. `A` flat surface of cylinder of radius `2a` and length `10a` will be an equipotential surface.

Points `A` and `B` are located on a circle forming flat surface of the cylinder. The electric field is perpendicular at all the points of this plane surface. Thus, there will be no-change in electrostic `PE` in moving the charge `+Q` on this plane surface.
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