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A point charge +Q is placed at point B a...

A point charge `+Q` is placed at point B at a distance 2R from the center O of an uncharged thin conducting shell of radius R as shown in figure. If VA be the potential at point A, which is at a radial distance of `R//2` from the center of the shell, then

A

`V_AgtQ/(8piepsilon_0R)`

B

`V_Alt Q/(8piepsilon_0R)`

C

`V_A=Q/(8piepsilon_0R)`

D

`V_A = 0`

Text Solution

Verified by Experts

The correct Answer is:
C
Since electric field inside the conducting shell is zero,
`V_(0)=V_(A)` and `V_(0)=(Q)/(8piepsilon_(0)R)`
`therefore V_(A)=(Q)/(8piepsilon_(0)R)`
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