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Uniform electric field exists in a regio...

Uniform electric field exists in a region and is given by `vecE = E_0hati + E_0hatj`. There are four points `A(-a,0), B(0,-a), C(a,0), and D(0,a)` in the xy plane. Which of the following is the correct relation for the electirc potential?

A

`V_A=V_CgtV_B=V_D`

B

`V_A=V_BgtV_C=V_D`

C

`V_AgtV_CgtV_B=V_D`

D

`V_AltV_CltV_BltV_D`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the electric potential at the four points A, B, C, and D in the given uniform electric field \( \vec{E} = E_0 \hat{i} + E_0 \hat{j} \). The relationship between electric field and electric potential is given by: \[ \vec{E} = -\nabla V \] This implies that the change in electric potential \( dV \) can be expressed as: \[ dV = -\vec{E} \cdot d\vec{r} \] Where \( d\vec{r} = dx \hat{i} + dy \hat{j} \). ### Step 1: Calculate the electric potential at each point 1. **Point A (-a, 0)**: \[ V_A = -\int_{(0,0)}^{(-a,0)} \vec{E} \cdot d\vec{r} \] \[ = -\int_0^{-a} E_0 \hat{i} \cdot dx \hat{i} - \int_0^{0} E_0 \hat{j} \cdot dy \hat{j} \] \[ = -(-E_0 a) = E_0 a \] 2. **Point B (0, -a)**: \[ V_B = -\int_{(0,0)}^{(0,-a)} \vec{E} \cdot d\vec{r} \] \[ = -\int_0^{0} E_0 \hat{i} \cdot dx \hat{i} - \int_0^{-a} E_0 \hat{j} \cdot dy \hat{j} \] \[ = -(-E_0 a) = E_0 a \] 3. **Point C (a, 0)**: \[ V_C = -\int_{(0,0)}^{(a,0)} \vec{E} \cdot d\vec{r} \] \[ = -\int_0^{a} E_0 \hat{i} \cdot dx \hat{i} - \int_0^{0} E_0 \hat{j} \cdot dy \hat{j} \] \[ = -E_0 a \] 4. **Point D (0, a)**: \[ V_D = -\int_{(0,0)}^{(0,a)} \vec{E} \cdot d\vec{r} \] \[ = -\int_0^{0} E_0 \hat{i} \cdot dx \hat{i} - \int_0^{a} E_0 \hat{j} \cdot dy \hat{j} \] \[ = -E_0 a \] ### Step 2: Summarize the potentials From our calculations, we have: - \( V_A = E_0 a \) - \( V_B = E_0 a \) - \( V_C = -E_0 a \) - \( V_D = -E_0 a \) ### Step 3: Establish the relations From the results: - \( V_A = V_B \) - \( V_C = V_D \) - \( V_A > V_C \) and \( V_B > V_D \) Thus, the correct relations for the electric potential are: \[ V_A = V_B > V_C = V_D \] ### Final Answer The correct relation for the electric potential is: \[ V_A = V_B > V_C = V_D \]

To solve the problem, we need to analyze the electric potential at the four points A, B, C, and D in the given uniform electric field \( \vec{E} = E_0 \hat{i} + E_0 \hat{j} \). The relationship between electric field and electric potential is given by: \[ \vec{E} = -\nabla V \] This implies that the change in electric potential \( dV \) can be expressed as: ...
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