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Charge over a nonconducting ring is dist...

Charge over a nonconducting ring is distributed so that the linear charge density varies as `lambda = lambda_0sin theta`. What is the direction of force on a charge `q_0` placed at the center?

A

along 1 if `q_0` is positive and 2 if `q_0` is negative.

B

along 2 if `q_0` is positive and 1 if `q_0` is negative.

C

along 3 if `q_0` is positive and 4 if `q_0` is negative.

D

along 4 if `q_0` is positive and 3 if `q_0` is negative.

Text Solution

Verified by Experts

The correct Answer is:
B
For `thetalethetalt2pi,lambda` is negative and symmmetrically distributed about `y-`axix.
Hence direction of electric Beld `E_("ne")` at `O` due to charge distribution is in downward direction, If `q_(0)` is `
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