Home
Class 12
PHYSICS
Five plates are arranged as shown in the...

Five plates are arranged as shown in the figure and connected across a battery of emf V. The separation between each plate is d and surface area of each plate is A.

A

Equivalent capacity between A and B is `epsilon_0A//5d`.

B

Equivalent capacity between A and B is `3epsilon_0A//5d`.

C

Charge on plate 1 is `epsilon_0AV//5d`

D

Charge on plate 3 is `3epsilon_0AV//5d`.

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
`C = (A epsilon_(0))/(d)`
`(1)/(C_(eq)) = (1)/(C ) + (2)/(3C) = (5)/(3C)`
Or `C_(eq) = (3C)/(5) = (3Aepsilon_(0))/(5d)`
Alternative method

`C_(ed) = (O)/(V) = (x + y)/(V_(AB))`
Potential of 1 and 4 is same
`(y)/(Aepsilon_(0)) = (2x)/(Aepsilon_(0))` or ` y = 2x`
`V = ((2 y + x)/(A epsilon_(0))) d, C_(eq) = ((x + 2x)A epsilon_(0))/((5x)d) = (3Aepsilon_(0))/(5d)`
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

Four identical metal plates are arranged as shown plates 1 and 4 are connected by a connecting wire. A battery of emf V volts is connected between plates 2 and 3. The electric field between plates 3 and 4 is (2V)/(Kd) . Find the value of K

Four large identical metallic plates are placed as shown in the Figure. Plate 2 is given a charge Q. All other plates are neutral. Now plates 1 and 4 are earthed. Area of each plate is A. (a) Find charge appearing on right side of plate 3. (b) Find potential difference between plates 1 and 2.

Shows an arrangement of identical metal plates paraed parallel to each other. The diagram also shows the variation of potential berween the plates . Using the details given in the diagram, find the equivalent capacitance connected across the battery (sepaaration between the consecutive plates is equal to l and the cross-sectional area of each plate is A). .

Two square plates of side 'a' are arranged as shown in the figure. The minimum separation between plates is 'd' and one of the plate is inclined at small angle alpha with plane parallel to another plate. The capacitance of capacitor is (given alpha is very small)

Six plates each of area A arranged as shown· in figure. The separation between adjoining plates is d . Find the equivalent capacitance between points A and B :

Four metal plates are arranged as shown in the figure. Capacitance between X and Y (Ararr" Area of each plate, d"rarr "distance between the plates") is

All the plates shown in the figure are parallel to each other, the area of each plate is A, and the separation between each pair of facing plates is d. The equivalent capacitance between points A and B is

The diagram shows an arrangement of identical metal plates placed parallel to each other and the variation of potential between the paltes by dotted lilne. Using the details given in diagram, the equivalent capacitance connected across the plate No. 2 and plate No. 4 is (Separation between the consecutive plates =L , area of each plate =A )

A parallel -plate capacitor with the plate area 100cm^2 and the separation between the plate 1.0cm is connected across a battery of emf 24 volts .Find the force of attraction between the plates.

Four metallic plates arearrranged as shown in the figure. If the distance between each plate then capacitance of the gives system between points A and B is (Given d lt lt A)

Home
Profile