Excess electrons are placed on a small lead sphere of mass `6.90 ` g so that its net charge is `-3.20 xx 10^(-9)C`. Find the number of excess electorns ( in terms of `xx 10^(10))` on the sphere.

Explanation

To find the number of excess electrons on a small lead sphere with a net charge of \(-3.20 \times 10^{-9} \, \text{C}\), we can follow these steps:

### Step 1: Understand the relationship between charge and number of electrons
The total charge \(Q\) on the sphere can be expressed in terms of the number of excess electrons \(n\) as:
\[ Q = n \cdot e \]
where \(e\) is the charge of a single electron, which is approximately \(1.6 \times 10^{-19} \, \text{C}\).
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