The electric field strength depends only on the x, y, and z coordinates according to the law `E = (a(xhati+yhatj+zhatk))/(x^2+y^2+z^2)^3//2`, where ` a = 280 Nm^2C^(-1)` is a constant. If the potential difference between (3,2,6) and (0,3,4) is `x^2`. What is the value of x.

Explanation

To solve the problem, we need to find the potential difference between the points (3, 2, 6) and (0, 3, 4) using the given electric field strength. The electric field is given by:

\[ E = \frac{a \cdot (x \hat{i} + y \hat{j} + z \hat{k})}{(x^2 + y^2 + z^2)^{3/2}} \]

where \( a = 280 \, \text{Nm}^2/\text{C} \).

...